Q. 34.8( 10 Votes )

In Fig. 16.178, <

Answer :

Given that,

O is the centre of the circle


We have,


BOD = 160o


By degree measure theorem,


BOD = 2 BCD


160o = 2x


x = 80o


Therefore,


BAD + BCD = 180o (Opposite angles of Cyclic quadrilateral)


y + x = 180o


y + 80o = 180o


y = 100o


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