Answer :
Since angles on the same segment of a circle are equal
Therefore,
∠CAD = ∠DBC = 55o
∠DAB = ∠CAD + ∠BAC
= 55o + 45o
= 100o
But,
∠DAB + ∠BCD = 180o (Opposite angles of a cyclic quadrilateral)
Therefore,
∠BCD = 180o – 100o
∠BCD = 80o
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