Q. 254.2( 9 Votes )
Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
∠ACB is an angle in minor segment
To prove: ∠ACB > 90o
Proof: By degree measure theorem
Reflex ∠AOB = 2 ∠ACB
Reflex ∠AOB > 180o
2 ∠ACB > 180o
∠ACB > 90o
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