# Prove that the angle in a segment shorter than a semicircle is greater than a right angle.

Given that,

ACB is an angle in minor segment

To prove: ACB > 90o

Proof: By degree measure theorem

Reflex AOB = 2 ACB

And,

Reflex AOB > 180o

Then,

2 ACB > 180o

ACB >

ACB > 90o

Hence, proved

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