Q. 225.0( 3 Votes )

If the two sides

Answer :

Given that,

ABCD is cyclic quadrilateral in which AB = DC


To prove: AC = BD


Proof: In and ,


AB = DC (Given)


BAP = CDP (Angles in the same segment)


PBA = PCD (Angles in the same segment)


Then,


(i) (By c.p.c.t)


(ii) (By c.p.c.t)


Adding (i) and (ii), we get


PA + PC = PD + PB


AC = BD


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