Answer :
WE have,
∠A - ∠C = 60o (i)
Since, ABCD is a cyclic quadrilateral
Then,
∠A + ∠C = 180o (ii)
Adding (i) and (ii), we get
∠A - ∠C + ∠A + ∠C = 60o + 180o
2 ∠A = 240o
∠A = 120o
Put value of ∠A in (ii), we get
120o + ∠C = 180o
∠C = 60o
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