Q. 154.8( 6 Votes )
There are three copies each of 4 different books. In how many ways can they be arranged in a shelf?
Given, that there are 4 different books each having 3 instances, having a total of 12 books.
Lets assume that there are 4 different books B1, B2, B3, and B4. So we have 12 books as -
B1, B1, B1, B2, B2, B2, B3, B3, B3, B4, B4, B4.
To find: Number of arrangements of these 12 books in such a way that all arrangements must be distinct.
The problem can now be rephrased as to find number of permutations of 12 objects in which 3 objects are of one type, 3 objects are of another type, 3 objects are of a third type, and remaining 3 objects are of different type.
Since we know, Permutation of n objects taking r at a time is nPr,and permuation of n objects taking all at a time is n!
And, we also know Permutation of n objects taking all at a time having p objects of same type, q objects of another type, r objects of another type is . i.e. the number of repeated objects of same type are in denominator multiplication with factorial.
The number of permutation of 12 objects with repeating books in factor of 3
Hence, total number of permutation of given 12 books will be equals to 369600.
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