Q. 12

# In Fig. 16.184, if *∠**BAC*=60° and *∠**BCA*=20°, find *∠**ADC*.

Answer :

By using angle sum property in triangle ABC,

∠B = 180^{o} – (60^{o} + 20^{o})

= 100^{o}

In cyclic quadrilateral ABCD, we have

∠B + ∠D = 180^{o}

∠D = 180^{o} – 100^{o}

= 100^{o}

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