Q. 114.6( 5 Votes )

A chord of a circ

Answer :

We have,

Radius OA = Chord AB


OA = OB = AB


Then, triangle OAB is an equilateral triangle


Therefore,


AOB = 60o (Angle of an equilateral triangle)


By degree measure theorem,


AOB = 2 APB


60o = 2 APB


APB = 30o


Now,


APB + AQB = 180o (Opposite angle of cyclic quadrilateral)


30o + AQB = 180o


AQB = 150o


Therefore,


Angle by chord AB at minor arc = 150o


And, by major arc = 30o


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