# In Fig. 16.120, <

APB = 50o (Given)

By degree measure theorem,

AOB = APB

APB = 2 * 50

= 100o

Since,

Hence,

OAB = OBA (Angle opposite to equal sides are equal)

Let,

OAB = x

In Triangle OAB,

OAB + OBA + AOB = 180o

x + x + 100o = 180o

2x = 80o

x = 40o

OAB = OBA = 40o

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