Answer :

Height of the frustum, h = 8m


Radii of frustum are: r’ = 13m and r’’ = 7m


Let l be the slant height of the frustum




l = 10cm


Curved surface area of frustum, A’ = π (r’ + r’’) × l


= π (13 + 7) × 10


= 628.57 cm2


Slant height of the conical cap = 12m


Base radius of the cap = 7m


Curved surface of the cap, A’’ = πrl


= π × 7 × 12


= 264m2


Total canvas required = A’ + A’’


= 628.57 + 264


= 892.57 m2


Total canvas = 892.57 m2


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