Q. 84.0( 20 Votes )

Three coins are tossed once. Find the probability of getting

(i) 3 heads

(ii) 2 heads

(iii) at least 2 heads

(iv) at most 2 heads

(v) no head

(vi) 3 tails

(vi) exactly two tails

(vii) (viii) no tail

(viii) (ix) at most two tails

Answer :

When three coins are tossed then S = {HHH, HHT, HTH, THH, TTH, HTT, TTT, THT}

Where s is sample space and here n(S) = 8


Let A be the event of getting 3 heads


n(A)= 1



Let A be the event of getting 2 heads


n (A) = 3



Let A be the event of getting at least 2 head


n(A) = 4



let A be the event of getting at most 2 heads


n(A) = 7



Let A be the event of getting no heads


n(A) = 1



(vi) Let A be the event of getting 3 tails


n(A) = 1



(vii) Let A be the event of getting exactly 2 tails


n(A) = 3



(viii) Let A be the event of getting no tails


n(A) = 1



(ix) Let A be the event of getting at most 2 tails


n(A) = 7



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