# A die is thrown; find the probability of following events:(i) A prime number will appear,(ii) A number greater than or equal to 3 will appear,(iii) A number less than or equal to one will appear,(iv) A number more than 6 will appear,(v) A number less than 6 will appear.

Here S = {1, 2, 3, 4, 5, 6}

n(S) = 6

(i) Let A be the event of getting a prime number,

A = {2, 3, 5} and n(A) = 3 (ii) Let A be the event of getting a number greater than or equal to 3,

Then A = (3, 4, 5, 6) and n(A) = 4 (iii) Let A be the event of getting a number less than or equal to 1,

Then A = (1) n (A) = 1 (iv) Let A be the event of getting a number more than 6, then

Then A = (0), n (A) = 0 (v) Let A be the event of getting a number less than 6, then

Then A= (1, 2, 3, 4, 5), n (A) = 5 Rate this question :

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