Q. 34.6( 16 Votes )

A die is thrown; find the probability of following events:

(i) A prime number will appear,

(ii) A number greater than or equal to 3 will appear,

(iii) A number less than or equal to one will appear,

(iv) A number more than 6 will appear,

(v) A number less than 6 will appear.

Answer :

Here S = {1, 2, 3, 4, 5, 6}

n(S) = 6


(i) Let A be the event of getting a prime number,


A = {2, 3, 5} and n(A) = 3



(ii) Let A be the event of getting a number greater than or equal to 3,


Then A = (3, 4, 5, 6) and n(A) = 4



(iii) Let A be the event of getting a number less than or equal to 1,


Then A = (1) n (A) = 1



(iv) Let A be the event of getting a number more than 6, then


Then A = (0), n (A) = 0



(v) Let A be the event of getting a number less than 6, then


Then A= (1, 2, 3, 4, 5), n (A) = 5


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