Answer :

Given: There are five children


To find: The number of ways in which these children can stand in a queue


Formula used:


Number of arrangements of n things taken all at a time = P(n, n)



The total number of ways in which five children can stand in a queue


= the number of arrangements of 5 things taken all at a time


= P(5, 5)




{ 0! = 1}


= 5!


= 5 × 4 × 3 × 2 × 1


= 120


Hence, Number of ways in which five children can stand in a queue are 120


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