Q. 1

Answer :

Radius of top of the bucket, r’ = 40/2 = 20 cm

Radius of bottom of the bucket, r’’ = 20/2 = 10 cm

Depth, h = 12cm

Volume of the bucket =

= 8800 cub. cm

Let l be slant height of the bucket

⇒ l = 15.62 cm

Total surface area of bucket = π (r’ + r’’) × l + π r’’^{2}

= π (20 + 10) × 15.620 + π (10)^{2}

= 17.81 dm^{2}

Cost of tin sheet = 1.20 × 17.87 = Rs21.40

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