Q. 35.0( 5 Votes )

Answer :

Given: height of the tent, H = 77dm = 7.7 m

Height of the cylindrical portion, h = 44dm = 4.4m

∴ Height of the conical portion, h’ = 7.7 – 4.4 = 3.3 m

Radius of the cylinder, r = 36/2 = 18m

Curved surface area of the cylindrical portion of the tent = 2 π r^{2} h

= 2 × π × (18)^{2} × 4.4

= 158.4 π m^{2}

Slant height of the conical portion of the tent =

= 18.3 m

∴ Curved surface area of the conical portion = π × 18 × 18.3

= 329.4 π m^{2}

∴ Total surface area of the tent = 158.4 π + 329.4 π

= 487.8 π

= 1533.09 m^{2}

∴ Canvas required to make the tent = 1533.09 m^{2}

Total cost of the canvas = 1533.09 × 3.50

= Rs5365.80

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