Answer :
Given that,
Distance (OC) = 5 cm
Radius of circle (OA) = 10 cm
In 
by using Pythagoras theorem
AC2 + OC2 = OA2
AC2 + 52 = 102
AC2 = 100 – 25
AC2 = 75
AC = 8.66 cm
We know that,
The perpendicular from centre to chord bisects the chord
Therefore,
AC = BC = 8.66 cm
Then,
Chord AB = 8.66 + 8.66
= 17.32 cm
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