Answer :




Radius of the cylinder portion (r) = 2.5 m


Height of the cylinder portion (h) = 21 m


Surface area of the cylindrical portion = 2πrh


= 2 × × 2.5 × 21 m


= 330 m ………(1)


Radius of the conical portion (r) = 2.5 m


Slant height of the conical portion (l) = 8 m


Curved surface area of the conical portion = πrl


= (22/7) × 2.5 × 8 m


= 62.86 m ……..(2)


Area of the circular top


= (22/7) × 2.5 × 2.5 m2


= 19.64 m2 ……………(3)


Total surface area of the rocket


= (330 + 62.86 + 19.64) m2 [From (1) , (2), (3)]


= 412.5 m2


Volume of the cylindrical portion h



= 412.5 m2

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