Answer :

Radius of the cylinder portion (r) = 2.5 m

Height of the cylinder portion (h) = 21 m

∴ Surface area of the cylindrical portion = 2πrh

= 2 × × 2.5 × 21 m

= 330 m ………(1)

Radius of the conical portion (r) = 2.5 m

Slant height of the conical portion (l) = 8 m

∴ Curved surface area of the conical portion = πrl

= (22/7) × 2.5 × 8 m

= 62.86 m ……..(2)

Area of the circular top

= (22/7) × 2.5 × 2.5 m^{2}

= 19.64 m^{2} ……………(3)

∴Total surface area of the rocket

= (330 + 62.86 + 19.64) m^{2} [From (1) , (2), (3)]

= 412.5 m^{2}

Volume of the cylindrical portion h

= 412.5 m^{2}

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