Answer :
Given that,
Radius of circle (OA) = 8 cm
Chord (AB) = 12 cm
Draw OC perpendicular to AB
We know that,
The perpendicular from centre to chord bisects the chord
Therefore,
AC = BC = 
= 6 cm
Now,
In 
, by using Pythagoras theorem
AC2 + OC2 = OA2
62 + OC2 = 82
36 + OC2 = 64
OC2 = 64 – 36
OC2 = 28
OC = 5.291 cm
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