Q. 524.9( 8 Votes )

Answer :

Height of the conical vessel, h’ = 11cm

It’s radius, r’ and r’’ resp.: r’ = 2.5cm r’’ = 0.25cm

Assume the number of spherical balls that were dropped in the vessel as ‘n’

Volume of water replaces by the spherical ball = volume of spherical balls dropped into the vessel

(2/5) × Volume of the cone = n × each spherical ball

⇒ (2.5)^{2} ×11 = n × 10 × (0.25)^{3}

⇒ n = 440

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