Q. 44.1( 29 Votes )

A room is 4.8 m long, 3.6 m broad and 2 m high. Find the cost of laying tiles on its floor and its four walls at the rate of ₹ 100/ m2.

Answer :

Given: Length (l) = 4.8m

Breadth (b) = 3.6m


Height (h) = 2m


Total Surface Area of the room = 2 {(l × b) + (b × h) + (h × l)}


But here we should not consider the ceiling of the room.


So, the required area of the room = lb + 2 (lh + bh)


= (4.8 × 3.6) + 2(4.8 × 2 + 3.6 × 2)


= 17.28 + 2 (9.6 + 7.2)


= 17.28 + 33.6


= 50.88 m2


Cost of laying tiles per square meter = ₹ 100


Cost of laying tiles for 50.88 m2= ₹100 × 50.88


= ₹5088


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Area of PolygonsArea of PolygonsArea of Polygons41 mins
Quiz | Imp. Qs on PolyhedronsQuiz | Imp. Qs on PolyhedronsQuiz | Imp. Qs on Polyhedrons38 mins
Quiz | MensurationQuiz | MensurationQuiz | Mensuration45 mins
Quiz | MensurationQuiz | MensurationQuiz | Mensuration43 mins
NCERT | Surface Area of Solid ShapesNCERT | Surface Area of Solid ShapesNCERT | Surface Area of Solid Shapes39 mins
NCERT | Imp. Qs. of MensurationNCERT | Imp. Qs. of MensurationNCERT | Imp. Qs. of Mensuration53 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :