Q. 44.1( 29 Votes )

# A room is 4.8 m long, 3.6 m broad and 2 m high. Find the cost of laying tiles on its floor and its four walls at the rate of ₹ 100/ m^{2}.

Answer :

Given: Length (l) = 4.8m

Breadth (b) = 3.6m

Height (h) = 2m

Total Surface Area of the room = **2 {(l × b) + (b × h) + (h × l)}**

But here we should **not** consider the ceiling of the room.

So, the required area of the room = **lb + 2 (lh + bh)**

= (4.8 × 3.6) + 2(4.8 × 2 + 3.6 × 2)

= 17.28 + 2 (9.6 + 7.2)

= 17.28 + 33.6

= 50.88 m^{2}

Cost of laying tiles per square meter = ₹ 100

Cost of laying tiles for 50.88 m^{2}= ₹100 × 50.88

= ₹5088

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