Answer :

Given: Length (l) = 8m

Breadth(b) = 5m

Height (h) = 4m

Firstly, we find the Lateral Surface Area of Cuboid i.e.

Area of Four Walls = **2h (l + b)**

= 2 × 4 (8+5)

= 8 (13)

= 104 m^{2}

Cost of distempering of 1 m^{2} area = ₹ 40

So, Cost of distempering of 104 m^{2} = ₹ 40 × 104 = ₹ 4160

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