Q. 20 4.2( 6 Votes )

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical ball is dropped into the tub and the level of the water is raised by 6.75 cm. Find the radius of the ball.

Answer :

Given, the radius of the cylindrical tube, r = 12cm

Level of water raised in tube, h = 6.75cm

Volume of cylinder = πr2 h

= π (12)2 × 6.75 cm3


let r be the radius of a spherical shell balls

volume of the sphere = -------(ii)

volume of cylinder = volume of spherical ball

r = 9cm

radius of spherical ball, r = 9cm

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