Q. 95.0( 1 Vote )

# Four candidates A

Answer :

Given that A is twice as likely to be selected as B

i.e. P(A) = 2 P(B) …(i)

and C is twice as likely to be selected as D

i.e. P(C) = 2P(D) …(ii)

Now, B and C are given about the same chance

P(B) = P(C) …(iii)

Since, sum of all probabilities = 1

P(A) + P(B) + P(C) + P(D) = 1

P(A) + P(B) + P(B) + P(D) = 1 [from (iii)] [from (i) & (ii)] [from (iii)] [from (i)] 9P(A) = 4 (a) P(C will be selected) = P(C)

= P(B) [from(iii)] [from(i)]  (b) P(A will not be selected) = P(A’)

= 1 – P(A)

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