Q. 95.0( 1 Vote )

Four candidates A

Answer :

Given that A is twice as likely to be selected as B

i.e. P(A) = 2 P(B) …(i)


and C is twice as likely to be selected as D


i.e. P(C) = 2P(D) …(ii)


Now, B and C are given about the same chance


P(B) = P(C) …(iii)


Since, sum of all probabilities = 1


P(A) + P(B) + P(C) + P(D) = 1


P(A) + P(B) + P(B) + P(D) = 1 [from (iii)]


[from (i) & (ii)]


[from (iii)]


[from (i)]



9P(A) = 4



(a) P(C will be selected) = P(C)


= P(B) [from(iii)]


[from(i)]




(b) P(A will not be selected) = P(A’)


= 1 – P(A)


[By complement Rule]





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