# AB is a chord of a circle with centre O and radius 4cm. AB is of length 4cm and divides the circle into two segments. Find the area of the minor segment.

Given: AB is a chord of a circle with centre O and radius 4cm. AB is of length 4cm and divides the circle into two segments.

To find: the area of the minor segment.

Solution:

Length of chord = 4cm

(Hence it makes an equilateral triangle at centre, in which all angle must be = 60°)

Area of sector =

Area of equilateral ∆OAB =

Area of minor segment = area of sector – area of ∆OAB

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