Q. 83.8( 10 Votes )
Prove that
</p
Answer :
(i) cos150
Sin150
Cos150 - sin150
(ii)cot105° - tan105° = cot(180° - 75°) - tan(180° - 75°)
(II quadrant tanx is negative and cotx as well)
= - cot75° - ( - tan75°)
= tan75° - cot75°
Tan75° = 
(using sin(90° - x) = - cosx and cos(90° - x) = sinx)
Cot75° = 
Cot105° - tan105° = 
(iii)
(II quadrant tanx negative)
- tan45° = - 1
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