# Find the probability that a leap year selected at random will contain 53 Sundays.

A leap year has 366 days with 52 weeks and 2 days.

Now, 52 weeks contains 52 Sundays.

The remaining two days can be:(i) Sunday and Monday, (ii) Monday and Tuesday, (iii) Tuesday and Wednesday, (iv) Wednesday and Thursday, (v) Thursday and Friday, (vi) Friday and Saturday,(vii) Saturday and Sunday

Let E be the event of getting a leap year with 53 Sundays

Total cases = 7

Number of favorable case, i.e. getting 53rd sunday = 2 [Sunday and Monday / Saturday and sunday]

P (a leap year having 53 Sundays) = P (E) = 2/7

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