Q. 254.6( 16 Votes )

Find the probability that a leap year selected at random will contain 53 Sundays.

Answer :

A leap year has 366 days with 52 weeks and 2 days.

Now, 52 weeks contains 52 Sundays.

The remaining two days can be:(i) Sunday and Monday, (ii) Monday and Tuesday, (iii) Tuesday and Wednesday, (iv) Wednesday and Thursday, (v) Thursday and Friday, (vi) Friday and Saturday,(vii) Saturday and Sunday

Let E be the event of getting a leap year with 53 Sundays

Total cases = 7

Number of favorable case, i.e. getting 53rd sunday = 2 [Sunday and Monday / Saturday and sunday]

P (a leap year having 53 Sundays) = P (E) = 2/7

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Imp. Qs. of ProbabilityQuiz | Imp. Qs. of ProbabilityQuiz | Imp. Qs. of Probability37 mins
Let's understand ProbabilityLet's understand ProbabilityLet's understand Probability40 mins
When Chance is called ProbabilityWhen Chance is called ProbabilityWhen Chance is called Probability48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses