Answer :

Let


Putting


Which implies,


A(x+1)(2x+3)+B(x-1)(2x+3)+C(x-1)(x+1)=2x-3


Now put x+1=0


Therefore, x=-1


A(0)+B(-1-1)(-2+3)+C(0)=-2-3



Now put x-1=0


Therefore, x=1


A(2)(2+3)+B(0)+C(0)=-1



Now put 2x+3=0


Therefore,





.Now From equation (1) we get,






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