Q. 505.0( 5 Votes )
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Answer :
let
Put t=cosx
dt=-sinxdx
Putting
A(1+t)(3+2t)+B(1-t)(3+2t)+C(1+t)(1-t)=1
Now Putting 1+t=0
t=-1
A(0)+B(2)(3-2)+C(0)=1
Now Putting 1-t=0
t=1
A(2)(5)+B(0)+C(0)=1
Now Putting 3+2t=0
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