Answer :

Let


Putting


Which implies,


A(x+2)(x-2)+B(x-1)(x-3)+C(x-1)(x+2)=2x-1


Now put x+2=0


Therefore, x=-2


A(0)+B(-2-1)(-2-3)+C(0)=2x-2-1


B(-3)(-5)=-5



Now put x-3=0


Therefore, x=3


A(0)+B(0)+C(2)(5)=5



Now put x-1=0


Therefore, x=1


A(3)(-2)+B(0)+C(0)=1



Now From equation (1) we get,





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