Answer :


Let

Put


A(x2+4)+(Bx+C)(2x+1) =17


Put 2x+1=0





A=4


By equating the coefficient of x2 and constant term,


A+2B=0


4+2B=0


B=-2


4A+C=17


4×4+C=17


C=1


From the equation(1), we get,






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