Answer :

Let


Putting


Which implies,


A(x-2)(x-4)+Bx(x-4)+Cx(x-2)=1


Now put x-2=0


Therefore, x=2


A(0)+B×2(2-4)+C(0)=1


B×2(-2)=1



Now put x-4=0


Therefore, x=4


A(0)+B×(0)+C×4(4-2)=1


C×4(2)=1



Now put x=0


A(0-2)(0-4)+B(0)+C(0)=1



Now From equation (1) we get





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