Answer :


Let


Now putting,


A(x2+1)+(Bx+C)(x-1)=3x+5


Putting x-1=0,


X=1


A(2)+B(0)=3+5=8


A=4


By equating the coefficient of x2 and constant term, A+B=0


4+B=0


B=-4


A-C=5


4-C=5


C=-1


From equation (1),we get,






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