Answer :


Let


Now putting,


A(x-1)2+B(2x-3)(x-1)+C(2x-3) = 5x2-18x+17


Putting x-1=0,


X=1


A(0)+B(0)+C(2-3)=5-18+17


C(-1)=4


Putting 2x-3=0,






A=5


By equating the coefficient of x2, we get ,


A+2B=5


5+2B=5


2B=0


B=0


From equation (1), we get,




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