Answer :


Let


Now putting,


Ax2+(Bx + C)(3x+8) = 5x+8


Putting 3x+8=0,







By equating the coefficient of x2 and constant term,


A+3B=0





8C=8


C=1


From equation (1), we get,





Putting x+2=0,


X=-2


A(-4)2+B(0)+C(0)=-6+1=-5



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