Answer :

Let


Now putting,


A(x-2)2+B(x+2)(x-2)+C(x+2)=3x+1


Putting x-2=0,


X=2


A(0)+B(0)+C(2+1)=3×2+1



Putting x+2=0,


X=-2


A(-4)2+B(0)+C(0)=-6+1=-5



By equation the coefficient of x2, we get, A+B=0





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