Answer :

Let


Now putting,


A(x-1)2+B(x+3)(x-1)+C(x+3)=x2+1


Now put x-1=0


Therefore, x=1


A(0)+B(0)+C(4) =2



Now put x+3=0


Therefore, x=-3


A(-3-1)2+B(0)+C(0) =9+1=10



By equating the coefficient of x2, we get, A+B=1




From equation (1), we get,





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