Answer :

When two coins are tossed simultaneously, all possible outcomes are HH, HT, TH, TT.

Total number of outcomes = 4

(i) Let E be the event for getting exactly 1 head

Then, the favourable outcomes are: HT, TH

Number of favourable outcomes = 2

∴ P(getting exactly one head) = P(E) = 2/4 = 1/2 or 50%

(ii) Let E be the event for getting atmost one head

Then, the favourable outcomes are: HT, TH, HH

Number of favourable outcomes = 3

∴ P(getting atmost one head) = P(E) = 3/4 or 75%

__Note: Atmost one means maximum one head can come. So, we will also consider the outcome in which no head is obtained.__

__Atleast one means minimum one head will come. So, the outcome with two heads will also be counted.__

(iii) Let E be the event for getting atleast one head

Then, the favourable outcomes are: HT, TH, HH

Number of favourable outcomes = 3

∴ P(getting atleast one head) = P(E) = 3/4 or 75%

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A child has a dieRS Aggarwal - Mathematics