Answer :

Let


Now putting,


A(x-3)2+B(x+2)(x-3)+C(x+2)=2x+9


Now put x-3=0


Therefore, x=3


A(0)+B(0)+C(3+2) =6+9=15


C=3


Now put x+2=0


Therefore, x=-2


A(-2-3)2+B(0)+C(0) = -4+9=5



Equating the coefficient of x2,we get,


A+B=0




From equation (1), we get,





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