Answer :


Let

Putting t=ex


dt=ex dx



Now putting,


A(t+1)(t-3)+B(t-1)(t-3)+C(t-1)(t+1)=1


Now put t+1=0


Therefore, t=-1


A(0)+B(-1-1)(-1-3)+C(0)=1


B(-2)(-4)=1



Now put t-1=0


Therefore, t=1


A(1+1)(1-3)+B(0)+C(0)=1



Now put t-3=0


Therefore, t=3


A(0)+B(0)+C(3-1)(3+1)=1



Now From equation (1) we get,






Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Evaluate thMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

If <img widMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Find :

Mathematics - Board Papers

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1