Q. 143.8( 9 Votes )

In a family of 3

Answer :

Let E be the event of having at least one boy

The probability that each child will be a boy is 1/2.


The probability that each child will be a girl is 1/2.


The probability of no boys = 1/2 × 1/2 × 1/2 = 1/8


Then, the number of favourable outcome is P(E) –P(not E)=1 where P(E) is probability of having at least one boy and P(not E) means the probability of having no boy at all.


Probability (at least 1 boy) = 1 - probability (no boys)= 1 - 1/8 = 7/8


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A child has a dieRS Aggarwal - Mathematics