Q. 85.0( 1 Vote )
Show that the solution set of the following system of linear inequalities is an unbounded region 2x + y≥ 8, x + 2y≥ 10, x ≥ 0, y ≥ 0.
Answer :
First we will find the solutions of the given equations by hit and trial method and afterwards we will plot the graph of the equations and shade the side with grey color containing common solutions or intersection of solution set of each inequality,
You can choose any value but find the two mandatory values which are at x = 0 and y = 0, i.e. x and y intercepts always,
2x + y≥ 8
x + 2y≥ 10
x ≥ 0, y ≥ 0.
Rate this question :
Interactive Quiz on Equations & inequations63 mins
Discussion | Miscellaneous Exercise | NCERT Chapter 6| Linear Inequalities33 mins
Concept of Linear momentum and its conservation40 mins
Check your understanding of linear momentum22 mins
Conservation of Linear Momentum, Visualize the concept (Theory + Interactive Quiz)41 mins
Show that the solution set of the following system of linear inequalities is an unbounded region 2x + y≥ 8, x + 2y≥ 10, x ≥ 0, y ≥ 0.
RD Sharma - Mathematicssolve the following systems of inequations graphically :
5x + y ≥ 10, 2x + 2y ≥ 12, x + 4y ≥ 12, x ≥ 0, y ≥ 0
RD Sharma - Mathematicssolve the following systems of inequations graphically :
x + 2y≤ 40,3x + y ≥ 30, 4x + 3y≥ 60, x ≥ 0, y ≥ 0
RD Sharma - Mathematicssolve the following systems of inequations graphically :
2x + y ≥ 8, x + 2y ≥ 8, x + y ≤ 6
RD Sharma - Mathematicssolve the following systems of inequations graphically :
12 + 12y ≤ 840, 3x + 6y ≤ 300,8x + 4y ≤ 480, x ≥ 0, y ≥ 0
RD Sharma - MathematicsFind the linear inequations for which the solution set is the shaded region given in Fig. 15.42.
Show that the following system of linear equations has no solution :
x + 2y ≥ 3, 3x + 4y ≥ 12, x ≥ 0, y ≥ 1.
RD Sharma - MathematicsShow that the solution set of the following linear inequations is an unbounded set :
x + y ≥ 9, 3x + y ≥ 12, x ≥ 0, y ≥ 0.
RD Sharma - Mathematics