# In a throw of a fair die, find the probability of getting(i) the number 5(ii) the number 3 or 4(iii) a prime number(iv) a number greater than 4(v) a number greater than 6(vi) a number less than 6

Outcomes (X) = 1,2,3,4,5,6

(i)The number 5 appers only once in a throw of dice So P(X)=

(ii) There are either chances of getting 3 or 4 P(X) =

(iii)Prime Number:- a number which is divisible by 1 or number itself.

So favourable cases are 2,3,5 P(X)=

(iv)Number greater than 4 are 5,6 so P(X)=

(v) A Dice contains only n1,2,3,4,5,6 as the number, so there is no chance of getting a number than 6 So P(X)=0

(vi) Since A Dice contains only n1,2,3,4,5,6 as the number So Number, less than 6 is P(X)=

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