Q. 54.2( 5 Votes )

In a simultaneous throw of two coins, find the probability of getting

(i) two heads

(ii) exactly one head

(iii) no tail

(iv) at least one tail

Answer :

(i) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Two heads occurs ony once so total number of favorable outcomes = 1


P(two heads)=


(ii) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Exactly one head occurs 2 times so a total number of favourable outcomes = 2.


P(exactly one head) = 2/4


(iii) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


No tails occurs only one time when there are two heads = 1


so total number of favourable outcomes = 1


P(no tails) = 1/4


(iv) Outcomes = (H,H), (H,T),(T,H),(T,T)


Total number of outcomes = 4


Atleast one tails occurs 3 times


so total number of favourable outcomes = 3


P(atleast 1 tail) = 1/4


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