Answer :

Observe that, from the given data:

The maximum class frequency, here, is 28 and the class corresponding to this frequency is 50 – 60.

So, this implies that,

Modal class = 50 – 60

Mode of such grouped frequency distribution is given by,

Where,

l = lower limit of the modal class = 50

f_{0} = frequency of the class preceding the modal class = 17

f_{1} = frequency of the modal class = 28

f_{2} = frequency of the class succeeding the modal class = 23

c = size of class interval (the class intervals are same) = 10

∴ Substituting the values l = 50, f_{0} = 17, f_{1} = 28, f_{2} = 23 and c = 10 in the formula of mode. We get

⇒

⇒

⇒

⇒ Mode = 50 + 6.875

⇒ Mode = 56.875

**Thus, the mode of the data is 56.875.**

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