Q. 1 B3.8( 9 Votes )

# Construct rectang

AB = 6 cm, AC = 7.2 cm

Construction:

1) Draw a line segment ‘AB’ of length ‘6’cm.

2) Draw a perpendicular line to ‘AB’ using Protractor at point ‘B’.

3) Now, taking ‘A’ as centre draw an arc of length ‘7.2’cm.

4) The arc will intersect the line at a point, this is the point ‘C’. Join the points ‘A’, ’C’ to form line segment ‘AC’ and ‘B’, ’C’ to form line segment ‘BC’.

5) Now draw perpendicular line to line segment ‘BC’ using protractor at point ‘C’.

6) Now draw perpendicular line to line segment ‘AB’ using protractor at point ‘A’.

7) These two perpendicular lines intersect at a point, this point is ‘D

8) Join points ‘A’, ’D’ to form line segment ‘AD’ and points ‘B’, ’D’ to form line segment ‘BD’.

9) Thus Rectangle ‘ABCD’ is formed.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

The sides of a reKarnataka Board - Mathematics Part II

| Construct squarKarnataka Board - Mathematics Part II

Construct rectangKarnataka Board - Mathematics Part II

All rectangles arKarnataka Board - Mathematics Part II

The side ofKarnataka Board - Mathematics Part II

In a rhombus ABCDKarnataka Board - Mathematics Part II

In a given squareKarnataka Board - Mathematics Part II

A rhombus is a paKarnataka Board - Mathematics Part II

| Construct squarKarnataka Board - Mathematics Part II

A rectangular yarKarnataka Board - Mathematics Part II