Answer :


Consider a square ABCD,


According to the problem, it is given that the area of ΔABD is 36cm2.


We know that the diagonal of a square bisect into congruent triangles.


So, from the figure we can clearly say that


Area of ΔABD = Area of ΔBCD


So, Area of ΔBCD = 36cm2.


From the figure, we can clearly say that,


Area of square ABCD = Area of ΔABD + Area of ΔBCD


Area of square ABCD = 36 + 36cm2


Area of square ABCD = 72cm2.


The Area of ΔBCD = 36cm2.


The Area of square ABCD = 72cm2.


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