Q. 94.3( 21 Votes )

# In a given square

Answer :

Consider a square **ABCD**,

According to the problem, it is given that the area of **ΔABD** is **36**cm^{2}.

We know that the diagonal of a square bisect into congruent triangles.

So, from the figure we can clearly say that

Area of **ΔABD** = Area of **ΔBCD**

So, Area of **ΔBCD** = **36**cm^{2}.

From the figure, we can clearly say that,

Area of square **ABCD** = Area of **ΔABD** + Area of **ΔBCD**

Area of square ABCD = 36 + 36cm^{2}

Area of square ABCD = 72cm^{2}.

The Area of **ΔBCD** = **36**cm^{2}.

The Area of square **ABCD** = **72**cm^{2}.

Rate this question :

The sides of a reKarnataka Board - Mathematics Part II

| Construct squarKarnataka Board - Mathematics Part II

Construct rectangKarnataka Board - Mathematics Part II

All rectangles arKarnataka Board - Mathematics Part II

The side ofKarnataka Board - Mathematics Part II

In a rhombus ABCDKarnataka Board - Mathematics Part II

In a given squareKarnataka Board - Mathematics Part II

A rhombus is a paKarnataka Board - Mathematics Part II

| Construct squarKarnataka Board - Mathematics Part II

A rectangular yarKarnataka Board - Mathematics Part II