Q. 64.0( 21 Votes )

# In a rhombus ABCD

Answer :

Given a rhombus **ABCD**,

According to the problem, it is given that **∠****C = 70 ^{0}**.

We know that in a rhombus, the sum of adjacent angles is **180 ^{0}**.

The opposite angles are equal.

So, we can say that;

**∠****A =** **∠****C**.

**∠****B =** **∠****D**.

**∠****C +** **∠****D = 180 ^{0}**.

From the values and equations, we can write that,

⇒ **∠****A = 70 ^{0}**.

⇒ 70^{0} + ∠D = 180^{0}

⇒ ∠D = 180^{0} - 70^{0}

⇒ **∠****D = 110 ^{0}**.

⇒ **∠****B = 110 ^{0}**.

The angles **∠****A**, **∠****B,** **∠****D** is **70 ^{0}, 110^{0}, 110^{0}**.

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