Answer :

Given,


Inside perimeter of track = 400m


Length of straight portion = 90m


Width of path = 14m


Total length of straight path = 90+90 = 180m


Remaining length = 400 – 180 = 220m


This length includes two semi circles or a complete circle.


So,


2πr = 220m



Then,


Area of path = (area of rectangles ABCD + rectangle EFGH + two semicircles)


= 14×90+14×90+π [(25+14)2 – 352]


[(a2 – b2) = (a+b)(a-b)]



Area of path = 6216m2


Length of outer track = 90+90+2πr


r = 35+14 = 49



= 180 +308 = 488m2


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