Q. 123.9( 15 Votes )

The inside perime

Answer :

Given,

Inside perimeter of track = 400m

Length of straight portion = 90m

Width of path = 14m

Total length of straight path = 90+90 = 180m

Remaining length = 400 – 180 = 220m

This length includes two semi circles or a complete circle.

So,

2πr = 220m

Then,

Area of path = (area of rectangles ABCD + rectangle EFGH + two semicircles)

= 14×90+14×90+π [(25+14)2 – 352]

[(a2 – b2) = (a+b)(a-b)]

Area of path = 6216m2

Length of outer track = 90+90+2πr

r = 35+14 = 49

= 180 +308 = 488m2

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