Answer :


Given:


Side(a) of square ABCD = 5cm.


Perimeter(P2) of square PQRS = 40cm.


We know that Perimeter of a square having side length ‘x’ is ‘4x’.


We also know that Area of a square having side length ‘x’ is ‘x2’.


So perimeter(P1) of square ABCD is 4a


i.e, P1 = 4a


P1 = 4 × 5


P1 = 20cm.


Area(A1) of square ABCD is a2


i.e, A1 = a2


A1 = 52


A1 = 25cm2.


Let's find the side length(b) of square PQRS


We have P2 = 4b


4b = 40


b =


b = 10cm.


Area(A2) of square PQRS is b2


i.e, A2 = b2


A2 = 102


A2 = 100cm2.


Let's find the ratio of Perimeters(RP) of both squares


i.e, rp =


rp =


rp =


Let's find the ratio of Areas(rA) of both squares


i.e., rag =


rag =


rag =


The ratio of perimeters is.


The ratio of area is.


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