# The side of

Given:

Side(a) of square ABCD = 5cm.

Perimeter(P2) of square PQRS = 40cm.

We know that Perimeter of a square having side length ‘x’ is ‘4x’.

We also know that Area of a square having side length ‘x’ is ‘x2’.

So perimeter(P1) of square ABCD is 4a

i.e, P1 = 4a

P1 = 4 × 5

P1 = 20cm.

Area(A1) of square ABCD is a2

i.e, A1 = a2

A1 = 52

A1 = 25cm2.

Let's find the side length(b) of square PQRS

We have P2 = 4b

4b = 40

b =

b = 10cm.

Area(A2) of square PQRS is b2

i.e, A2 = b2

A2 = 102

A2 = 100cm2.

Let's find the ratio of Perimeters(RP) of both squares

i.e, rp =

rp =

rp =

Let's find the ratio of Areas(rA) of both squares

i.e., rag =

rag =

rag =

The ratio of perimeters is.

The ratio of area is.

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