Answer :

Consider a triangle ABCD,


According to the problem, it is given that the sides are in the ratio 2:1.


The perimeter of the rectangle 30cm.



We know that the sides of the rectangles are represented by Length(L) and Breadth(B).


We also know that,


Perimeter(P) of the rectangle = 2 × (L + B).


From the problem, we came to know that the ratio L: B = 2:1.


Let us assume the values of Length and Breadth be 2x and.


From the problem, we have P = 30cm.


Substituting the values we get,


30 = 2 × (2x + x)


30 = 2 × (3x)


30 = 6x



x = 5cm.


Using the value of ‘x’ we find the value of length and breadth of Rectangle.


Now,


L = 2x


L = 2 × 5


L = 10cm.


B = 5cm.


From this, we can say that AB and CD are lengths, while BC and DA are breadths.


The lengths of AB, BC, CD, DA are 10cm, 5cm, 10cm, 5cm.


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