Q. 14.1( 21 Votes )

# The sides o

Consider a triangle ABCD,

According to the problem, it is given that the sides are in the ratio 2:1.

The perimeter of the rectangle 30cm.

We know that the sides of the rectangles are represented by Length(L) and Breadth(B).

We also know that,

Perimeter(P) of the rectangle = 2 × (L + B).

From the problem, we came to know that the ratio L: B = 2:1.

Let us assume the values of Length and Breadth be 2x and.

From the problem, we have P = 30cm.

Substituting the values we get,

30 = 2 × (2x + x)

30 = 2 × (3x)

30 = 6x

x = 5cm.

Using the value of ‘x’ we find the value of length and breadth of Rectangle.

Now,

L = 2x

L = 2 × 5

L = 10cm.

B = 5cm.

From this, we can say that AB and CD are lengths, while BC and DA are breadths.

The lengths of AB, BC, CD, DA are 10cm, 5cm, 10cm, 5cm.

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